5G PSS Vs SSS Vs ESS | Difference Between PSS, SSS, ESS In 5G

compares 5G PSS vs SSS vs ESS and mentions difference between PSS, SSS, ESS in 5G. PSS stands for Primary Synchronization Signal, SSS stands for Secondary Synchronization Signal and ESS stands for Extended Synchronization Signal.

Radio frame in 5G-TF is 10ms in duration. It has total 100 slots or 50 subframes. Each subframe consists of two consecutive slots. Each slot has 7 OFDM symbols in normal cyclic prefix. Each resource block houses 12 subcarriers and 7 symbols.

Resource Grid:
The transmitted signal in each slot is described by one or several resource grids of (NRB)DL * (NSC)RB = 1200 subcarriers and (NSymb)DL =7 OFDM symbols.
Resource Element:
Each element in resource grid for antenna port-p is known as resource element and it is uniquely identified by index pair (k,l) in one slot where, k = 0, ...., (NRB)DL * (NSC)RB -1 and l = 0, ....., (NSymb)DL -1 are indices in frequency domain and time domain respectively.

Primary Synchronization Signal | PSS In 5G

• It is constructed using 62 subcarriers based on Zadoff Chu Sequence.
• PSS is transmitted on all the OFDM symbols unlike LTE where in it is transmitted on one OFDM symbol only. Refer LTE PSS And SSS >> for more information.
• It is used to acquire symbol timing of a downlink frame.
• It is transmitted in symbol 0 to 13 in subframes number 0 and 25 and on antenna ports p = 300 to 313.

Secondary Synchronization Signal | SSS In 5G

• It is constructed using 62 data as per "Gold Sequence" and occupies 62 subcarriers.
• Like PSS, it is also used for radio frame synchronization.
• It is transmitted in symbol 0 to 13 in subframes number 0 and 25 and on antenna ports p = 300 to 313.

Extended Synchronization Signal | ESS In 5G

• ESS is new type of synchronization signal which is not used in LTE technology.
• It is used to identify OFDM symbol index.
• It is transmitted in symbols 0 to 13 in subframes 0 and 25 on antenna ports 300 to 313.
• The sequence used to obtain ESS is length 63 Zadoff Chu Sequence as expressed by
d(n) = e -j*{(25*π*n*(n+1))/63}
Where, n = 0,1,....,62.

Reference: TS V5G.211 V1.7